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Other Ways to Solve
Polynomial long divisionStep by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
y-((4*x^4+7*x^2+4)/(2*x^2+x+2))=0
Step 1 :
Equation at the end of step 1 :
(((4•(x4))+(7•(x2)))+4) y-——————————————————————— = 0 ((2x2+x)+2)Step 2 :
Equation at the end of step 2 :
(((4•(x4))+7x2)+4) y-—————————————————— = 0 (2x2+x+2)Step 3 :
Equation at the end of step 3 :
((22x4 + 7x2) + 4)
y - —————————————————— = 0
(2x2 + x + 2)
Step 4 :
4x4 + 7x2 + 4
Simplify —————————————
2x2 + x + 2
Trying to factor by splitting the middle term
4.1 Factoring 4x4 + 7x2 + 4
The first term is, 4x4 its coefficient is 4 .
The middle term is, +7x2 its coefficient is 7 .
The last term, "the constant", is +4
Step-1 : Multiply the coefficient of the first term by the constant 4 • 4 = 16
Step-2 : Find two factors of 16 whose sum equals the coefficient of the middle term, which is 7 .
-16 | + | -1 | = | -17 | ||
-8 | + | -2 | = | -10 | ||
-4 | + | -4 | = | -8 | ||
-2 | + | -8 | = | -10 | ||
-1 | + | -16 | = | -17 | ||
1 | + | 16 | = | 17 | ||
2 | + | 8 | = | 10 | ||
4 | + | 4 | = | 8 | ||
8 | + | 2 | = | 10 | ||
16 | + | 1 | = | 17 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Trying to factor by splitting the middle term
4.2 Factoring 2x2+x+2
The first term is, 2x2 its coefficient is 2 .
The middle term is, +x its coefficient is 1 .
The last term, "the constant", is +2
Step-1 : Multiply the coefficient of the first term by the constant 2 • 2 = 4
Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is 1 .
-4 | + | -1 | = | -5 | ||
-2 | + | -2 | = | -4 | ||
-1 | + | -4 | = | -5 | ||
1 | + | 4 | = | 5 | ||
2 | + | 2 | = | 4 | ||
4 | + | 1 | = | 5 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Polynomial Long Division :
4.3 Polynomial Long Division
Dividing : 4x4+7x2+4
("Dividend")
By : 2x2+x+2 ("Divisor")
dividend | 4x4 | + | 7x2 | + | 4 | ||||||
- divisor | * 2x2 | 4x4 | + | 2x3 | + | 4x2 | |||||
remainder | - | 2x3 | + | 3x2 | + | 4 | |||||
- divisor | * -x1 | - | 2x3 | - | x2 | - | 2x | ||||
remainder | 4x2 | + | 2x | + | 4 | ||||||
- divisor | * 2x0 | 4x2 | + | 2x | + | 4 | |||||
remainder | 0 |
Quotient : 2x2-x+2
Remainder : 0
Equation at the end of step 4 :
y - (2x2 - x + 2) = 0
Step 5 :
Equation at the end of step 5 :
y - 2x2 + x - 2 = 0
Step 6 :
Solving a Single Variable Equation :
6.1 Solve y-2x2+x-2 = 0
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
We shall not handle this type of equations at this time.
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