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Nonlinear equations

Step by Step Solution

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "x4"   was replaced by   "x^4". 

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     x^2*x-12-(x^4)=0 

Step  1  :

Step  2  :

Pulling out like terms :

 2.1     Pull out like factors :

   -x4 + x3 - 12  =   -1 • (x4 - x3 + 12) 

Polynomial Roots Calculator :

 2.2    Find roots (zeroes) of :       F(x) = x4 - x3 + 12
Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  12.

 
The factor(s) are:

of the Leading Coefficient :  1
 
of the Trailing Constant :  1 ,2 ,3 ,4 ,6 ,12

 
Let us test ....

  P  Q  P/Q  F(P/Q)   Divisor
     -1     1      -1.00      14.00   
     -2     1      -2.00      36.00   
     -3     1      -3.00      120.00   
     -4     1      -4.00      332.00   
     -6     1      -6.00      1524.00   
     -12     1     -12.00     22476.00   
     1     1      1.00      12.00   
     2     1      2.00      20.00   
     3     1      3.00      66.00   
     4     1      4.00      204.00   
     6     1      6.00      1092.00   
     12     1      12.00     19020.00   


Polynomial Roots Calculator found no rational roots

Equation at the end of step  2  :

  -x4 + x3 - 12  = 0 

Step  3  :

Quartic Equations :

 3.1     Solve   -x4+x3-12 = 0

In search of an interavl at which the above polynomial changes sign, from negative to positive or the other wayaround.

Method of search: Calculate polynomial values for all integer points between x=-20 and x=+20

No interval at which a change of sign occures has been found. Consequently, Bisection Approximation can not be used. As this is a polynomial of an even degree it may not even have any real (as opposed to imaginary) roots

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