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Other Ways to Solve
Nonlinear equationsStep by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x4" was replaced by "x^4".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
x^2*x-12-(x^4)=0
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
-x4 + x3 - 12 = -1 • (x4 - x3 + 12)
Polynomial Roots Calculator :
2.2 Find roots (zeroes) of : F(x) = x4 - x3 + 12
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is 12.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,4 ,6 ,12
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | 14.00 | ||||||
-2 | 1 | -2.00 | 36.00 | ||||||
-3 | 1 | -3.00 | 120.00 | ||||||
-4 | 1 | -4.00 | 332.00 | ||||||
-6 | 1 | -6.00 | 1524.00 | ||||||
-12 | 1 | -12.00 | 22476.00 | ||||||
1 | 1 | 1.00 | 12.00 | ||||||
2 | 1 | 2.00 | 20.00 | ||||||
3 | 1 | 3.00 | 66.00 | ||||||
4 | 1 | 4.00 | 204.00 | ||||||
6 | 1 | 6.00 | 1092.00 | ||||||
12 | 1 | 12.00 | 19020.00 |
Polynomial Roots Calculator found no rational roots
Equation at the end of step 2 :
-x4 + x3 - 12 = 0
Step 3 :
Quartic Equations :
3.1 Solve -x4+x3-12 = 0
In search of an interavl at which the above polynomial changes sign, from negative to positive or the other wayaround.
Method of search: Calculate polynomial values for all integer points between x=-20 and x=+20
No interval at which a change of sign occures has been found. Consequently, Bisection Approximation can not be used. As this is a polynomial of an even degree it may not even have any real (as opposed to imaginary) roots
No solutions found
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