Solution - Quadratic equations
Step by Step Solution
Step by step solution :
Step 1 :
Trying to factor by splitting the middle term
1.1 Factoring x2+100x-300000
The first term is, x2 its coefficient is 1 .
The middle term is, +100x its coefficient is 100 .
The last term, "the constant", is -300000
Step-1 : Multiply the coefficient of the first term by the constant 1 • -300000 = -300000
Step-2 : Find two factors of -300000 whose sum equals the coefficient of the middle term, which is 100 .
-300000 | + | 1 | = | -299999 | ||
-150000 | + | 2 | = | -149998 | ||
-100000 | + | 3 | = | -99997 | ||
-75000 | + | 4 | = | -74996 | ||
-60000 | + | 5 | = | -59995 | ||
-50000 | + | 6 | = | -49994 | ||
-37500 | + | 8 | = | -37492 | ||
-30000 | + | 10 | = | -29990 | ||
-25000 | + | 12 | = | -24988 | ||
-20000 | + | 15 | = | -19985 | ||
-18750 | + | 16 | = | -18734 | ||
-15000 | + | 20 | = | -14980 | ||
-12500 | + | 24 | = | -12476 | ||
-12000 | + | 25 | = | -11975 | ||
-10000 | + | 30 | = | -9970 | ||
-9375 | + | 32 | = | -9343 | ||
-7500 | + | 40 | = | -7460 | ||
-6250 | + | 48 | = | -6202 | ||
-6000 | + | 50 | = | -5950 | ||
-5000 | + | 60 | = | -4940 | ||
-4000 | + | 75 | = | -3925 | ||
-3750 | + | 80 | = | -3670 | ||
-3125 | + | 96 | = | -3029 | ||
-3000 | + | 100 | = | -2900 | ||
-2500 | + | 120 | = | -2380 | ||
-2400 | + | 125 | = | -2275 | ||
-2000 | + | 150 | = | -1850 | ||
-1875 | + | 160 | = | -1715 | ||
-1500 | + | 200 | = | -1300 | ||
-1250 | + | 240 | = | -1010 | ||
-1200 | + | 250 | = | -950 | ||
-1000 | + | 300 | = | -700 | ||
-800 | + | 375 | = | -425 | ||
-750 | + | 400 | = | -350 | ||
-625 | + | 480 | = | -145 | ||
-600 | + | 500 | = | -100 | ||
-500 | + | 600 | = | 100 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -500 and 600
x2 - 500x + 600x - 300000
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-500)
Add up the last 2 terms, pulling out common factors :
600 • (x-500)
Step-5 : Add up the four terms of step 4 :
(x+600) • (x-500)
Which is the desired factorization
Equation at the end of step 1 :
(x + 600) • (x - 500) = 0
Step 2 :
Theory - Roots of a product :
2.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
2.2 Solve : x+600 = 0
Subtract 600 from both sides of the equation :
x = -600
Solving a Single Variable Equation :
2.3 Solve : x-500 = 0
Add 500 to both sides of the equation :
x = 500
Supplement : Solving Quadratic Equation Directly
Solving x2+100x-300000 = 0 directly
Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula
Parabola, Finding the Vertex :
3.1 Find the Vertex of y = x2+100x-300000
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is -50.0000
Plugging into the parabola formula -50.0000 for x we can calculate the y -coordinate :
y = 1.0 * -50.00 * -50.00 + 100.0 * -50.00 - 300000.0
or y = -302500.000
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = x2+100x-300000
Axis of Symmetry (dashed) {x}={-50.00}
Vertex at {x,y} = {-50.00,-302500.00}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-600.00, 0.00}
Root 2 at {x,y} = {500.00, 0.00}
Solve Quadratic Equation by Completing The Square
3.2 Solving x2+100x-300000 = 0 by Completing The Square .
Add 300000 to both side of the equation :
x2+100x = 300000
Now the clever bit: Take the coefficient of x , which is 100 , divide by two, giving 50 , and finally square it giving 2500
Add 2500 to both sides of the equation :
On the right hand side we have :
300000 + 2500 or, (300000/1)+(2500/1)
The common denominator of the two fractions is 1 Adding (300000/1)+(2500/1) gives 302500/1
So adding to both sides we finally get :
x2+100x+2500 = 302500
Adding 2500 has completed the left hand side into a perfect square :
x2+100x+2500 =
(x+50) • (x+50) =
(x+50)2
Things which are equal to the same thing are also equal to one another. Since
x2+100x+2500 = 302500 and
x2+100x+2500 = (x+50)2
then, according to the law of transitivity,
(x+50)2 = 302500
We'll refer to this Equation as Eq. #3.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x+50)2 is
(x+50)2/2 =
(x+50)1 =
x+50
Now, applying the Square Root Principle to Eq. #3.2.1 we get:
x+50 = √ 302500
Subtract 50 from both sides to obtain:
x = -50 + √ 302500
Since a square root has two values, one positive and the other negative
x2 + 100x - 300000 = 0
has two solutions:
x = -50 + √ 302500
or
x = -50 - √ 302500
Solve Quadratic Equation using the Quadratic Formula
3.3 Solving x2+100x-300000 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 1
B = 100
C = -300000
Accordingly, B2 - 4AC =
10000 - (-1200000) =
1210000
Applying the quadratic formula :
-100 ± √ 1210000
x = —————————
2
Can √ 1210000 be simplified ?
Yes! The prime factorization of 1210000 is
2•2•2•2•5•5•5•5•11•11
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 1210000 = √ 2•2•2•2•5•5•5•5•11•11 =2•2•5•5•11•√ 1 =
± 1100 • √ 1 =
± 1100
So now we are looking at:
x = ( -100 ± 1100) / 2
Two real solutions:
x =(-100+√1210000)/2=-50+550= 500.000
or:
x =(-100-√1210000)/2=-50-550= -600.000
Two solutions were found :
- x = 500
- x = -600
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