Solution - Other Factorizations
-x^2*(4x^31+1)*(4x^31-1)
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x6" was replaced by "x^6".
Step 1 :
Equation at the end of step 1 :
(x2) - 24x64Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
x2 - 16x64 = -x2 • (16x62 - 1)
Trying to factor as a Difference of Squares :
3.2 Factoring: 16x62 - 1
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 16 is the square of 4
Check : 1 is the square of 1
Check : x62 is the square of x31
Factorization is : (4x31 + 1) • (4x31 - 1)
Final result :
-x2 • (4x31 + 1) • (4x31 - 1)
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