Solution - Adding, subtracting and finding the least common multiple
Step by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :
x/4-(1/2)>0
Step by step solution :
Step 1 :
1
Simplify —
2
Equation at the end of step 1 :
x 1
— - — > 0
4 2
Step 2 :
x
Simplify —
4
Equation at the end of step 2 :
x 1
— - — > 0
4 2
Step 3 :
Calculating the Least Common Multiple :
3.1 Find the Least Common Multiple
The left denominator is : 4
The right denominator is : 2
| Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
|---|---|---|---|
| 2 | 2 | 1 | 2 |
| Product of all Prime Factors | 4 | 2 | 4 |
Least Common Multiple:
4
Calculating Multipliers :
3.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 1
Right_M = L.C.M / R_Deno = 2
Making Equivalent Fractions :
3.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. x —————————————————— = — L.C.M 4 R. Mult. • R. Num. 2 —————————————————— = — L.C.M 4
Adding fractions that have a common denominator :
3.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x - (2) x - 2
——————— = —————
4 4
Equation at the end of step 3 :
x - 2
————— > 0
4
Step 4 :
4.1 Multiply both sides by 4
Solve Basic Inequality :
4.2 Add 2 to both sides
x > 2
Inequality Plot :
4.3 Inequality plot for
0.250 x - 0.500 > 0
One solution was found :
x > 2How did we do?
Please leave us feedback.