Solution - Quadratic equations

Step by step solution :

Step  1  :

Trying to factor by splitting the middle term

 1.1     Factoring  n²+601n-16200 

The first term is,  n²  its coefficient is  1 .
The middle term is,  +601n  its coefficient is  601 .
The last term, "the constant", is  -16200 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -16200 = -16200 

Step-2 : Find two factors of  -16200  whose sum equals the coefficient of the middle term, which is   601 .

For tidiness, printing of 54 lines which failed to find two such factors, was suppressed

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Equation at the end of step  1  :

  n2 + 601n - 16200  = 0 

Step  2  :

Parabola, Finding the Vertex :

 2.1      Find the Vertex of   y = n²+601n-16200

Parabolas have a highest or a lowest point called the Vertex .   Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) .   We know this even before plotting  "y"  because the coefficient of the first term, 1 , is positive (greater than zero). 

 Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions. 

 Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex. 

 For any parabola,An²+Bn+C,the  n -coordinate of the vertex is given by  -B/(2A) . In our case the  n  coordinate is  -300.5000  

 Plugging into the parabola formula  -300.5000  for  n  we can calculate the  y -coordinate : 
  y = 1.0 * -300.50 * -300.50 + 601.0 * -300.50 - 16200.0
or   y = -106500.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = n²+601n-16200
Axis of Symmetry (dashed)  {n}={-300.50} 
Vertex at  {n,y} = {-300.50,-106500.25} 
 n -Intercepts (Roots) :
Root 1 at  {n,y} = {-626.84, 0.00} 
Root 2 at  {n,y} = {25.84, 0.00} 

Solve Quadratic Equation by Completing The Square

 2.2     Solving   n²+601n-16200 = 0 by Completing The Square .

 Add  16200  to both side of the equation :
   n²+601n = 16200

Now the clever bit: Take the coefficient of  n , which is  601 , divide by two, giving  601/2 , and finally square it giving  601/2 

Add  601/2  to both sides of the equation :
  On the right hand side we have :
   16200  +  601/2    or,  (16200/1)+(601/2) 
  The common denominator of the two fractions is  2   Adding  (32400/2)+(601/2)  gives  33001/2 
  So adding to both sides we finally get :
   n²+601n+(601/2) = 33001/2

Adding  601/2  has completed the left hand side into a perfect square :
   n²+601n+(601/2)  =
   (n+(601/2)) • (n+(601/2))  =
  (n+(601/2))²
Things which are equal to the same thing are also equal to one another. Since
   n²+601n+(601/2) = 33001/2 and
   n²+601n+(601/2) = (n+(601/2))²
then, according to the law of transitivity,
   (n+(601/2))² = 33001/2

We'll refer to this Equation as  Eq. #2.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of
   (n+(601/2))²   is
   (n+(601/2))^2/2 =
  (n+(601/2))¹ =
   n+(601/2)

Now, applying the Square Root Principle to  Eq. #2.2.1  we get:
   n+(601/2) = √ 33001/2

Subtract  601/2  from both sides to obtain:
   n = -601/2 + √ 33001/2

Since a square root has two values, one positive and the other negative
   n² + 601n - 16200 = 0
   has two solutions:
  n = -601/2 + √ 33001/2
   or
  n = -601/2 - √ 33001/2

Note that  √ 33001/2 can be written as
  √ 33001  / √ 2 

Solve Quadratic Equation using the Quadratic Formula

 2.3     Solving    n²+601n-16200 = 0 by the Quadratic Formula .

 According to the Quadratic Formula,  n  , the solution for   An²+Bn+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :
                                     
            - B  ±  √ B²-4AC
  n =   ————————
                      2A

  In our case,  A   =     1
                      B   =   601
                      C   =  -16200

Accordingly,  B²  -  4AC   =
                     361201 - (-64800) =
                     426001

Applying the quadratic formula :

               -601 ± √ 426001
   n  =    —————————
                          2

  √ 426001   , rounded to 4 decimal digits, is  652.6875
 So now we are looking at:
           n  =  ( -601 ±  652.688 ) / 2

Two real solutions:

 n =(-601+√426001)/2=25.844

or:

 n =(-601-√426001)/2=-626.844

Two solutions were found :

1.  n =(-601-√426001)/2=-626.844
2.  n =(-601+√426001)/2=25.844