Solution - Reducing fractions to their lowest terms
Step by Step Solution
Step 1 :
6
Simplify ——
a2
Equation at the end of step 1 :
6
((a2) + 1) - ——
a2
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using a2 as the denominator :
a2 + 1 (a2 + 1) • a2
a2 + 1 = —————— = —————————————
1 a2
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Polynomial Roots Calculator :
2.2 Find roots (zeroes) of : F(a) = a2 + 1
Polynomial Roots Calculator is a set of methods aimed at finding values of a for which F(a)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 2.00 | ||||||
| 1 | 1 | 1.00 | 2.00 |
Polynomial Roots Calculator found no rational roots
Adding fractions that have a common denominator :
2.3 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
(a2+1) • a2 - (6) a4 + a2 - 6
————————————————— = ———————————
a2 a2
Trying to factor by splitting the middle term
2.4 Factoring a4 + a2 - 6
The first term is, a4 its coefficient is 1 .
The middle term is, +a2 its coefficient is 1 .
The last term, "the constant", is -6
Step-1 : Multiply the coefficient of the first term by the constant 1 • -6 = -6
Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is 1 .
| -6 | + | 1 | = | -5 | ||
| -3 | + | 2 | = | -1 | ||
| -2 | + | 3 | = | 1 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 3
a4 - 2a2 + 3a2 - 6
Step-4 : Add up the first 2 terms, pulling out like factors :
a2 • (a2-2)
Add up the last 2 terms, pulling out common factors :
3 • (a2-2)
Step-5 : Add up the four terms of step 4 :
(a2+3) • (a2-2)
Which is the desired factorization
Polynomial Roots Calculator :
2.5 Find roots (zeroes) of : F(a) = a2+3
See theory in step 2.2
In this case, the Leading Coefficient is 1 and the Trailing Constant is 3.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,3
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 4.00 | ||||||
| -3 | 1 | -3.00 | 12.00 | ||||||
| 1 | 1 | 1.00 | 4.00 | ||||||
| 3 | 1 | 3.00 | 12.00 |
Polynomial Roots Calculator found no rational roots
Trying to factor as a Difference of Squares :
2.6 Factoring: a2-2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 2 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares.
Final result :
(a2 + 3) • (a2 - 2)
———————————————————
a2
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