Solution - Factoring binomials using the difference of squares
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x4" was replaced by "x^4".
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(9 • (x2)) - (22•3x4) = 0Step 2 :
Equation at the end of step 2 :
32x2 - (22•3x4) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
9x2 - 12x4 = -3x2 • (4x2 - 3)
Trying to factor as a Difference of Squares :
4.2 Factoring: 4x2 - 3
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 4 is the square of 2
Check : 3 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares.
Equation at the end of step 4 :
-3x2 • (4x2 - 3) = 0
Step 5 :
Theory - Roots of a product :
5.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
5.2 Solve : -3x2 = 0
Multiply both sides of the equation by (-1) : 3x2 = 0
Divide both sides of the equation by 3:
x2 = 0
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:
x = ± √ 0
Any root of zero is zero. This equation has one solution which is x = 0
Solving a Single Variable Equation :
5.3 Solve : 4x2-3 = 0
Add 3 to both sides of the equation :
4x2 = 3
Divide both sides of the equation by 4:
x2 = 3/4 = 0.750
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:
x = ± √ 3/4
The equation has two real solutions
These solutions are x = ±√ 0.750 = ± 0.86603
Three solutions were found :
- x = ±√ 0.750 = ± 0.86603
- x = 0
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