Solution - Simplification or other simple results

Step  1  :

Equation at the end of step  1  :

  (32a2 +  6a) +  1

Step  2  :

Trying to factor by splitting the middle term

 2.1     Factoring  9a²+6a+1 

The first term is,  9a²  its coefficient is  9 .
The middle term is,  +6a  its coefficient is  6 .
The last term, "the constant", is  +1 

Step-1 : Multiply the coefficient of the first term by the constant   9 • 1 = 9 

Step-2 : Find two factors of  9  whose sum equals the coefficient of the middle term, which is   6 .

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  3  and  3 
                     9a² + 3a + 3a + 1

Step-4 : Add up the first 2 terms, pulling out like factors :
                    3a • (3a+1)
              Add up the last 2 terms, pulling out common factors :
                     1 • (3a+1)
Step-5 : Add up the four terms of step 4 :
                    (3a+1)  •  (3a+1)
             Which is the desired factorization

Multiplying Exponential Expressions :

 2.2    Multiply  (3a+1)  by  (3a+1) 

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (3a+1)  and the exponents are :
          1 , as  (3a+1)  is the same number as  (3a+1)¹ 
 and   1 , as  (3a+1)  is the same number as  (3a+1)¹ 
The product is therefore,  (3a+1)⁽¹⁺¹⁾ = (3a+1)² 

Final result :

  (3a + 1)2