Solution - Adding, subtracting and finding the least common multiple
Step by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :
8/5-(s+12/5)>0
Step by step solution :
Step 1 :
12
Simplify ——
5
Equation at the end of step 1 :
8 12
— - (s + ——) > 0
5 5
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Adding a fraction to a whole
Rewrite the whole as a fraction using 5 as the denominator :
s s • 5
s = — = —————
1 5
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
s • 5 + 12 5s + 12
—————————— = ———————
5 5
Equation at the end of step 2 :
8 (5s + 12)
— - ————————— > 0
5 5
Step 3 :
8
Simplify —
5
Equation at the end of step 3 :
8 (5s + 12)
— - ————————— > 0
5 5
Step 4 :
Adding fractions which have a common denominator :
4.1 Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
8 - ((5s+12)) -5s - 4
————————————— = ———————
5 5
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
-5s - 4 = -1 • (5s + 4)
Equation at the end of step 5 :
-5s - 4
——————— > 0
5
Step 6 :
6.1 Multiply both sides by 5
6.2 Multiply both sides by (-1)
Flip the inequality sign since you are multiplying by a negative number
5s+4 < 0
6.3 Divide both sides by 5
s+(4/5) < 0
Solve Basic Inequality :
6.4 Subtract 4/5 from both sides
s < -4/5
Inequality Plot :
6.5 Inequality plot for
-s - 0.800 > 0
One solution was found :
s < -4/5How did we do?
Please leave us feedback.