Solution - Adding, subtracting and finding the least common multiple
Step by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
7*b-2/5-(6*b-7/5)=0
Step by step solution :
Step 1 :
7
Simplify —
5
Equation at the end of step 1 :
2 7
(7b - —) - (6b - —) = 0
5 5
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 5 as the denominator :
6b 6b • 5
6b = —— = ——————
1 5
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
6b • 5 - (7) 30b - 7
———————————— = ———————
5 5
Equation at the end of step 2 :
2 (30b - 7)
(7b - —) - ————————— = 0
5 5
Step 3 :
2
Simplify —
5
Equation at the end of step 3 :
2 (30b - 7)
(7b - —) - ————————— = 0
5 5
Step 4 :
Rewriting the whole as an Equivalent Fraction :
4.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 5 as the denominator :
7b 7b • 5
7b = —— = ——————
1 5
Adding fractions that have a common denominator :
4.2 Adding up the two equivalent fractions
7b • 5 - (2) 35b - 2
———————————— = ———————
5 5
Equation at the end of step 4 :
(35b - 2) (30b - 7)
————————— - ————————— = 0
5 5
Step 5 :
Adding fractions which have a common denominator :
5.1 Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
(35b-2) - ((30b-7)) 5b + 5
——————————————————— = ——————
5 5
Step 6 :
Pulling out like terms :
6.1 Pull out like factors :
5b + 5 = 5 • (b + 1)
Equation at the end of step 6 :
b + 1 = 0
Step 7 :
Solving a Single Variable Equation :
7.1 Solve : b+1 = 0
Subtract 1 from both sides of the equation :
b = -1
One solution was found :
b = -1How did we do?
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