Solution - Simplification or other simple results
Step by Step Solution
Step 1 :
Equation at the end of step 1 :
((2•3a2) - 11a) - 10
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 6a2-11a-10
The first term is, 6a2 its coefficient is 6 .
The middle term is, -11a its coefficient is -11 .
The last term, "the constant", is -10
Step-1 : Multiply the coefficient of the first term by the constant 6 • -10 = -60
Step-2 : Find two factors of -60 whose sum equals the coefficient of the middle term, which is -11 .
| -60 | + | 1 | = | -59 | ||
| -30 | + | 2 | = | -28 | ||
| -20 | + | 3 | = | -17 | ||
| -15 | + | 4 | = | -11 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and 4
6a2 - 15a + 4a - 10
Step-4 : Add up the first 2 terms, pulling out like factors :
3a • (2a-5)
Add up the last 2 terms, pulling out common factors :
2 • (2a-5)
Step-5 : Add up the four terms of step 4 :
(3a+2) • (2a-5)
Which is the desired factorization
Final result :
(2a - 5) • (3a + 2)
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