Solution - Reducing fractions to their lowest terms
Other Ways to Solve
Reducing fractions to their lowest termsStep by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "62.5" was replaced by "(625/10)".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
(625/10)-(k^56)=0
Step by step solution :
Step 1 :
125
Simplify ———
2
Equation at the end of step 1 :
125
——— - k56 = 0
2
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 2 as the denominator :
k56 k56 • 2
k56 = ——— = ———————
1 2
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
125 - (k56 • 2) 125 - 2k56
——————————————— = ——————————
2 2
Trying to factor as a Difference of Squares :
2.3 Factoring: 125 - 2k56
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 125 is not a square !!
Ruling : Binomial can not be factored as the
difference of two perfect squares
Equation at the end of step 2 :
125 - 2k56
—————————— = 0
2
Step 3 :
When a fraction equals zero :
3.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
125-2k56
———————— • 2 = 0 • 2
2
Now, on the left hand side, the 2 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
125-2k56 = 0
Solving a Single Variable Equation :
3.2 Solve : -2k56+125 = 0
Subtract 125 from both sides of the equation :
-2k56 = -125
Multiply both sides of the equation by (-1) : 2k56 = 125
Divide both sides of the equation by 2:
k56 = 125/2 = 62.500
k = 56th root of (125/2)
The equation has two real solutions
These solutions are k = 56th root of (62.500) = ± 1.07664
Two solutions were found :
k = 56th root of (62.500) = ± 1.07664How did we do?
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