Solution - Simplification or other simple results
Step by Step Solution
Step 1 :
Equation at the end of step 1 :
(22y2 + 26y) + 30
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
4y2 + 26y + 30 = 2 • (2y2 + 13y + 15)
Trying to factor by splitting the middle term
3.2 Factoring 2y2 + 13y + 15
The first term is, 2y2 its coefficient is 2 .
The middle term is, +13y its coefficient is 13 .
The last term, "the constant", is +15
Step-1 : Multiply the coefficient of the first term by the constant 2 • 15 = 30
Step-2 : Find two factors of 30 whose sum equals the coefficient of the middle term, which is 13 .
| -30 | + | -1 | = | -31 | ||
| -15 | + | -2 | = | -17 | ||
| -10 | + | -3 | = | -13 | ||
| -6 | + | -5 | = | -11 | ||
| -5 | + | -6 | = | -11 | ||
| -3 | + | -10 | = | -13 | ||
| -2 | + | -15 | = | -17 | ||
| -1 | + | -30 | = | -31 | ||
| 1 | + | 30 | = | 31 | ||
| 2 | + | 15 | = | 17 | ||
| 3 | + | 10 | = | 13 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 10
2y2 + 3y + 10y + 15
Step-4 : Add up the first 2 terms, pulling out like factors :
y • (2y+3)
Add up the last 2 terms, pulling out common factors :
5 • (2y+3)
Step-5 : Add up the four terms of step 4 :
(y+5) • (2y+3)
Which is the desired factorization
Final result :
2 • (2y + 3) • (y + 5)
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