Solution - Quadratic equations
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "1.44" was replaced by "(144/100)".
Step by step solution :
Step 1 :
36
Simplify ——
25
Equation at the end of step 1 :
36 ((4 • (x2)) + 3x) - —— = 0 25Step 2 :
Equation at the end of step 2 :
36
(22x2 + 3x) - —— = 0
25
Step 3 :
Rewriting the whole as an Equivalent Fraction :
3.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 25 as the denominator :
4x2 + 3x (4x2 + 3x) • 25
4x2 + 3x = ———————— = ———————————————
1 25
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
4x2 + 3x = x • (4x + 3)
Adding fractions that have a common denominator :
4.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x • (4x+3) • 25 - (36) 100x2 + 75x - 36
—————————————————————— = ————————————————
25 25
Trying to factor by splitting the middle term
4.3 Factoring 100x2 + 75x - 36
The first term is, 100x2 its coefficient is 100 .
The middle term is, +75x its coefficient is 75 .
The last term, "the constant", is -36
Step-1 : Multiply the coefficient of the first term by the constant 100 • -36 = -3600
Step-2 : Find two factors of -3600 whose sum equals the coefficient of the middle term, which is 75 .
-3600 | + | 1 | = | -3599 | ||
-1800 | + | 2 | = | -1798 | ||
-1200 | + | 3 | = | -1197 | ||
-900 | + | 4 | = | -896 | ||
-720 | + | 5 | = | -715 | ||
-600 | + | 6 | = | -594 |
For tidiness, printing of 39 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 4 :
100x2 + 75x - 36
———————————————— = 0
25
Step 5 :
When a fraction equals zero :
5.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
100x2+75x-36
———————————— • 25 = 0 • 25
25
Now, on the left hand side, the 25 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
100x2+75x-36 = 0
Parabola, Finding the Vertex :
5.2 Find the Vertex of y = 100x2+75x-36
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 100 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is -0.3750
Plugging into the parabola formula -0.3750 for x we can calculate the y -coordinate :
y = 100.0 * -0.38 * -0.38 + 75.0 * -0.38 - 36.0
or y = -50.062
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 100x2+75x-36
Axis of Symmetry (dashed) {x}={-0.38}
Vertex at {x,y} = {-0.38,-50.06}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-1.08, 0.00}
Root 2 at {x,y} = { 0.33, 0.00}
Solve Quadratic Equation by Completing The Square
5.3 Solving 100x2+75x-36 = 0 by Completing The Square .
Divide both sides of the equation by 100 to have 1 as the coefficient of the first term :
x2+(3/4)x-(9/25) = 0
Add 9/25 to both side of the equation :
x2+(3/4)x = 9/25
Now the clever bit: Take the coefficient of x , which is 3/4 , divide by two, giving 3/8 , and finally square it giving 9/64
Add 9/64 to both sides of the equation :
On the right hand side we have :
9/25 + 9/64 The common denominator of the two fractions is 1600 Adding (576/1600)+(225/1600) gives 801/1600
So adding to both sides we finally get :
x2+(3/4)x+(9/64) = 801/1600
Adding 9/64 has completed the left hand side into a perfect square :
x2+(3/4)x+(9/64) =
(x+(3/8)) • (x+(3/8)) =
(x+(3/8))2
Things which are equal to the same thing are also equal to one another. Since
x2+(3/4)x+(9/64) = 801/1600 and
x2+(3/4)x+(9/64) = (x+(3/8))2
then, according to the law of transitivity,
(x+(3/8))2 = 801/1600
We'll refer to this Equation as Eq. #5.3.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x+(3/8))2 is
(x+(3/8))2/2 =
(x+(3/8))1 =
x+(3/8)
Now, applying the Square Root Principle to Eq. #5.3.1 we get:
x+(3/8) = √ 801/1600
Subtract 3/8 from both sides to obtain:
x = -3/8 + √ 801/1600
Since a square root has two values, one positive and the other negative
x2 + (3/4)x - (9/25) = 0
has two solutions:
x = -3/8 + √ 801/1600
or
x = -3/8 - √ 801/1600
Note that √ 801/1600 can be written as
√ 801 / √ 1600 which is √ 801 / 40
Solve Quadratic Equation using the Quadratic Formula
5.4 Solving 100x2+75x-36 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 100
B = 75
C = -36
Accordingly, B2 - 4AC =
5625 - (-14400) =
20025
Applying the quadratic formula :
-75 ± √ 20025
x = ————————
200
Can √ 20025 be simplified ?
Yes! The prime factorization of 20025 is
3•3•5•5•89
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 20025 = √ 3•3•5•5•89 =3•5•√ 89 =
± 15 • √ 89
√ 89 , rounded to 4 decimal digits, is 9.4340
So now we are looking at:
x = ( -75 ± 15 • 9.434 ) / 200
Two real solutions:
x =(-75+√20025)/200=-3/8+3/40√ 89 = 0.333
or:
x =(-75-√20025)/200=-3/8-3/40√ 89 = -1.083
Two solutions were found :
- x =(-75-√20025)/200=-3/8-3/40√ 89 = -1.083
- x =(-75+√20025)/200=-3/8+3/40√ 89 = 0.333
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