Solution - Quadratic equations
Step by Step Solution
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(25x2 - 178x) - 125 = 0
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 32x2-178x-125
The first term is, 32x2 its coefficient is 32 .
The middle term is, -178x its coefficient is -178 .
The last term, "the constant", is -125
Step-1 : Multiply the coefficient of the first term by the constant 32 • -125 = -4000
Step-2 : Find two factors of -4000 whose sum equals the coefficient of the middle term, which is -178 .
-4000 | + | 1 | = | -3999 | ||
-2000 | + | 2 | = | -1998 | ||
-1000 | + | 4 | = | -996 | ||
-800 | + | 5 | = | -795 | ||
-500 | + | 8 | = | -492 | ||
-400 | + | 10 | = | -390 |
For tidiness, printing of 18 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 2 :
32x2 - 178x - 125 = 0
Step 3 :
Parabola, Finding the Vertex :
3.1 Find the Vertex of y = 32x2-178x-125
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 32 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 2.7812
Plugging into the parabola formula 2.7812 for x we can calculate the y -coordinate :
y = 32.0 * 2.78 * 2.78 - 178.0 * 2.78 - 125.0
or y = -372.531
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 32x2-178x-125
Axis of Symmetry (dashed) {x}={ 2.78}
Vertex at {x,y} = { 2.78,-372.53}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-0.63, 0.00}
Root 2 at {x,y} = { 6.19, 0.00}
Solve Quadratic Equation by Completing The Square
3.2 Solving 32x2-178x-125 = 0 by Completing The Square .
Divide both sides of the equation by 32 to have 1 as the coefficient of the first term :
x2-(89/16)x-(125/32) = 0
Add 125/32 to both side of the equation :
x2-(89/16)x = 125/32
Now the clever bit: Take the coefficient of x , which is 89/16 , divide by two, giving 89/32 , and finally square it giving 7921/1024
Add 7921/1024 to both sides of the equation :
On the right hand side we have :
125/32 + 7921/1024 The common denominator of the two fractions is 1024 Adding (4000/1024)+(7921/1024) gives 11921/1024
So adding to both sides we finally get :
x2-(89/16)x+(7921/1024) = 11921/1024
Adding 7921/1024 has completed the left hand side into a perfect square :
x2-(89/16)x+(7921/1024) =
(x-(89/32)) • (x-(89/32)) =
(x-(89/32))2
Things which are equal to the same thing are also equal to one another. Since
x2-(89/16)x+(7921/1024) = 11921/1024 and
x2-(89/16)x+(7921/1024) = (x-(89/32))2
then, according to the law of transitivity,
(x-(89/32))2 = 11921/1024
We'll refer to this Equation as Eq. #3.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x-(89/32))2 is
(x-(89/32))2/2 =
(x-(89/32))1 =
x-(89/32)
Now, applying the Square Root Principle to Eq. #3.2.1 we get:
x-(89/32) = √ 11921/1024
Add 89/32 to both sides to obtain:
x = 89/32 + √ 11921/1024
Since a square root has two values, one positive and the other negative
x2 - (89/16)x - (125/32) = 0
has two solutions:
x = 89/32 + √ 11921/1024
or
x = 89/32 - √ 11921/1024
Note that √ 11921/1024 can be written as
√ 11921 / √ 1024 which is √ 11921 / 32
Solve Quadratic Equation using the Quadratic Formula
3.3 Solving 32x2-178x-125 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 32
B = -178
C = -125
Accordingly, B2 - 4AC =
31684 - (-16000) =
47684
Applying the quadratic formula :
178 ± √ 47684
x = ————————
64
Can √ 47684 be simplified ?
Yes! The prime factorization of 47684 is
2•2•7•13•131
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 47684 = √ 2•2•7•13•131 =
± 2 • √ 11921
√ 11921 , rounded to 4 decimal digits, is 109.1833
So now we are looking at:
x = ( 178 ± 2 • 109.183 ) / 64
Two real solutions:
x =(178+√47684)/64=(89+√ 11921 )/32= 6.193
or:
x =(178-√47684)/64=(89-√ 11921 )/32= -0.631
Two solutions were found :
- x =(178-√47684)/64=(89-√ 11921 )/32= -0.631
- x =(178+√47684)/64=(89+√ 11921 )/32= 6.193
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