Solution - Linear equations with one unknown

Step by step solution :

Step  1  :

Equation at the end of step  1  :

  31y2 +  25y  = 0 

Step  2  :

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   31y² + 25y  =   y • (31y + 25) 

Equation at the end of step  3  :

  y • (31y + 25)  = 0 

Step  4  :

Theory - Roots of a product :

 4.1    A product of several terms equals zero. 

 When a product of two or more terms equals zero, then at least one of the terms must be zero. 

 We shall now solve each term = 0 separately 

 In other words, we are going to solve as many equations as there are terms in the product 

 Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

 4.2      Solve  :    y = 0 

  Solution is  y = 0

Solving a Single Variable Equation :

 4.3      Solve  :    31y+25 = 0 

 Subtract  25  from both sides of the equation : 
                      31y = -25
Divide both sides of the equation by 31:
                     y = -25/31 = -0.806

Two solutions were found :

1.  y = -25/31 = -0.806
   
2.  y = 0