Solution - Other Factorizations
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x8" was replaced by "x^8".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
2^3*x^8-(16)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(23 • x8) - 16 = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
8x8 - 16 = 8 • (x8 - 2)
Trying to factor as a Difference of Squares :
3.2 Factoring: x8 - 2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 2 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares.
Polynomial Roots Calculator :
3.3 Find roots (zeroes) of : F(x) = x8 - 2
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is -2.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | -1.00 | ||||||
-2 | 1 | -2.00 | 254.00 | ||||||
1 | 1 | 1.00 | -1.00 | ||||||
2 | 1 | 2.00 | 254.00 |
Polynomial Roots Calculator found no rational roots
Equation at the end of step 3 :
8 • (x8 - 2) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 8 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
4.2 Solve : x8-2 = 0
Add 2 to both sides of the equation :
x8 = 2
x = 8th root of (2)
The equation has two real solutions
These solutions are x = ± 8th root of 2 = ± 1.0905
Two solutions were found :
x = ± 8th root of 2 = ± 1.0905How did we do?
Please leave us feedback.