Solution - Adding, subtracting and finding the least common multiple
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "0.75" was replaced by "(75/100)". 2 more similar replacement(s)
Step by step solution :
Step 1 :
3
Simplify —
4
Equation at the end of step 1 :
15 3
20 • ((0 - (—— • r)) + —) = 0
10 4
Step 2 :
3
Simplify —
2
Equation at the end of step 2 :
3 3
20 • ((0 - (— • r)) + —) = 0
2 4
Step 3 :
Calculating the Least Common Multiple :
3.1 Find the Least Common Multiple
The left denominator is : 2
The right denominator is : 4
Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
2 | 1 | 2 | 2 |
Product of all Prime Factors | 2 | 4 | 4 |
Least Common Multiple:
4
Calculating Multipliers :
3.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 2
Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
3.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. -3r • 2 —————————————————— = ——————— L.C.M 4 R. Mult. • R. Num. 3 —————————————————— = — L.C.M 4
Adding fractions that have a common denominator :
3.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
-3r • 2 + 3 3 - 6r
——————————— = ——————
4 4
Equation at the end of step 3 :
(3 - 6r)
20 • ———————— = 0
4
Step 4 :
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
3 - 6r = -3 • (2r - 1)
Equation at the end of step 5 :
-15 • (2r - 1) = 0
Step 6 :
Equations which are never true :
6.1 Solve : -15 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
6.2 Solve : 2r-1 = 0
Add 1 to both sides of the equation :
2r = 1
Divide both sides of the equation by 2:
r = 1/2 = 0.500
One solution was found :
r = 1/2 = 0.500How did we do?
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