Solution - Simplification or other simple results
5*(3y^2+4y-5)
Step by Step Solution
Step 1 :
Equation at the end of step 1 :
((3•5y2) + 20y) - 25
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
15y2 + 20y - 25 = 5 • (3y2 + 4y - 5)
Trying to factor by splitting the middle term
3.2 Factoring 3y2 + 4y - 5
The first term is, 3y2 its coefficient is 3 .
The middle term is, +4y its coefficient is 4 .
The last term, "the constant", is -5
Step-1 : Multiply the coefficient of the first term by the constant 3 • -5 = -15
Step-2 : Find two factors of -15 whose sum equals the coefficient of the middle term, which is 4 .
| -15 | + | 1 | = | -14 | ||
| -5 | + | 3 | = | -2 | ||
| -3 | + | 5 | = | 2 | ||
| -1 | + | 15 | = | 14 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
5 • (3y2 + 4y - 5)
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