Solution - Power equations
1/(2^20*5^20*631)=1.58479*10^-23
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "^-8" was replaced by "^(-8))". 1 more similar replacement(s)
(2): "6.31" was replaced by "(631/100)".
Step 1 :
1.1 10 = 2•5
(10)-8 = (2•5)(-8) = (2)(-8) • (5)(-8)
Equation at the end of step 1 :
631
(1 • ———) • ((2)(-8)•(5)(-8))
100
Step 2 :
631
Simplify ———
100
Equation at the end of step 2 :
631
(1 • ———) • ((2)(-8)•(5)(-8))
100
Step 3 :
3.1 10 = 2•5
(10)-14 = (2•5)(-14) = (2)(-14) • (5)(-14)
Equation at the end of step 3 :
631
(1 • ———) • ((2)(-8)•(5)(-8))
100
Step 4 :
1 631
Divide ————————— by ———
(214•514) 100
4.1 Dividing fractions
To divide fractions, write the divison as multiplication by the reciprocal of the divisor :
1 631 1 100 ————————— ÷ ——— = ————————— • ——— (214•514) 100 (214•514) 631
Dividing exponents :
4.2 22 divided by 214 = 2(2 - 14) = 2(-12) = 1/212
Dividing exponents :
4.3 52 divided by 514 = 5(2 - 14) = 5(-12) = 1/512
Equation at the end of step 4 :
1
(1 • —————————————) • ((2)(-8)•(5)(-8))
(212•512•631)
Step 5 :
Multiplying exponents :
5.1 212 multiplied by 28 = 2(12 + 8) = 220
Multiplying exponents :
5.2 512 multiplied by 58 = 5(12 + 8) = 520
Final result :
1
————————————— = 1.58479 • 10-23
(220•520•631)
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