Solution - Linear equations with one unknown

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "0.2" was replaced by "(2/10)".

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     -5*(y+(2/10))-(25)=0 

Step by step solution :

Step  1  :

            1
 Simplify   —
            5

Equation at the end of step  1  :

                   1       
  (0 -  (5 • (y +  —))) -  25  = 0 
                   5       

Step  2  :

Rewriting the whole as an Equivalent Fraction :

 2.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  5  as the denominator :

          y     y • 5
     y =  —  =  —————
          1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

 2.2       Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 y • 5 + 1     5y + 1
 —————————  =  ——————
     5           5   

Equation at the end of step  2  :

             (5y + 1)      
  (0 -  (5 • ————————)) -  25  = 0 
                5          

Step  3  :

Equation at the end of step  3  :

  (0 -  (5y + 1)) -  25  = 0 

Step  4  :

Step  5  :

Pulling out like terms :

 5.1     Pull out like factors :

   -5y - 26  =   -1 • (5y + 26) 

Equation at the end of step  5  :

  -5y - 26  = 0 

Step  6  :

Solving a Single Variable Equation :

 6.1      Solve  :    -5y-26 = 0 

 Add  26  to both sides of the equation : 
                      -5y = 26
Multiply both sides of the equation by (-1) :  5y = -26


Divide both sides of the equation by 5:
                     y = -26/5 = -5.200

One solution was found :