Solution - Simplification or other simple results
-2*(2t^2-t-12)
Step by Step Solution
Step 1 :
Equation at the end of step 1 :
((0 - 22t2) + 2t) + 24
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
-4t2 + 2t + 24 = -2 • (2t2 - t - 12)
Trying to factor by splitting the middle term
3.2 Factoring 2t2 - t - 12
The first term is, 2t2 its coefficient is 2 .
The middle term is, -t its coefficient is -1 .
The last term, "the constant", is -12
Step-1 : Multiply the coefficient of the first term by the constant 2 • -12 = -24
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is -1 .
| -24 | + | 1 | = | -23 | ||
| -12 | + | 2 | = | -10 | ||
| -8 | + | 3 | = | -5 | ||
| -6 | + | 4 | = | -2 | ||
| -4 | + | 6 | = | 2 | ||
| -3 | + | 8 | = | 5 | ||
| -2 | + | 12 | = | 10 | ||
| -1 | + | 24 | = | 23 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
-2 • (2t2 - t - 12)
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