Solution - Quadratic equations
Step by Step Solution
Step by step solution :
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
-x2 - 44x + 340 = -1 • (x2 + 44x - 340)
Trying to factor by splitting the middle term
2.2 Factoring x2 + 44x - 340
The first term is, x2 its coefficient is 1 .
The middle term is, +44x its coefficient is 44 .
The last term, "the constant", is -340
Step-1 : Multiply the coefficient of the first term by the constant 1 • -340 = -340
Step-2 : Find two factors of -340 whose sum equals the coefficient of the middle term, which is 44 .
| -340 | + | 1 | = | -339 | ||
| -170 | + | 2 | = | -168 | ||
| -85 | + | 4 | = | -81 | ||
| -68 | + | 5 | = | -63 | ||
| -34 | + | 10 | = | -24 | ||
| -20 | + | 17 | = | -3 | ||
| -17 | + | 20 | = | 3 | ||
| -10 | + | 34 | = | 24 | ||
| -5 | + | 68 | = | 63 | ||
| -4 | + | 85 | = | 81 | ||
| -2 | + | 170 | = | 168 | ||
| -1 | + | 340 | = | 339 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 2 :
-x2 - 44x + 340 = 0
Step 3 :
Parabola, Finding the Vertex :
3.1 Find the Vertex of y = -x2-44x+340
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens down and accordingly has a highest point (AKA absolute maximum) . We know this even before plotting "y" because the coefficient of the first term, -1 , is negative (smaller than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is -22.0000
Plugging into the parabola formula -22.0000 for x we can calculate the y -coordinate :
y = -1.0 * -22.00 * -22.00 - 44.0 * -22.00 + 340.0
or y = 824.000
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = -x2-44x+340
Axis of Symmetry (dashed) {x}={-22.00}
Vertex at {x,y} = {-22.00,824.00}
x -Intercepts (Roots) :
Root 1 at {x,y} = { 6.71, 0.00}
Root 2 at {x,y} = {-50.71, 0.00}
Solve Quadratic Equation by Completing The Square
3.2 Solving -x2-44x+340 = 0 by Completing The Square .
Multiply both sides of the equation by (-1) to obtain positive coefficient for the first term:
x2+44x-340 = 0 Add 340 to both side of the equation :
x2+44x = 340
Now the clever bit: Take the coefficient of x , which is 44 , divide by two, giving 22 , and finally square it giving 484
Add 484 to both sides of the equation :
On the right hand side we have :
340 + 484 or, (340/1)+(484/1)
The common denominator of the two fractions is 1 Adding (340/1)+(484/1) gives 824/1
So adding to both sides we finally get :
x2+44x+484 = 824
Adding 484 has completed the left hand side into a perfect square :
x2+44x+484 =
(x+22) • (x+22) =
(x+22)2
Things which are equal to the same thing are also equal to one another. Since
x2+44x+484 = 824 and
x2+44x+484 = (x+22)2
then, according to the law of transitivity,
(x+22)2 = 824
We'll refer to this Equation as Eq. #3.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x+22)2 is
(x+22)2/2 =
(x+22)1 =
x+22
Now, applying the Square Root Principle to Eq. #3.2.1 we get:
x+22 = √ 824
Subtract 22 from both sides to obtain:
x = -22 + √ 824
Since a square root has two values, one positive and the other negative
x2 + 44x - 340 = 0
has two solutions:
x = -22 + √ 824
or
x = -22 - √ 824
Solve Quadratic Equation using the Quadratic Formula
3.3 Solving -x2-44x+340 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = -1
B = -44
C = 340
Accordingly, B2 - 4AC =
1936 - (-1360) =
3296
Applying the quadratic formula :
44 ± √ 3296
x = ——————
-2
Can √ 3296 be simplified ?
Yes! The prime factorization of 3296 is
2•2•2•2•2•103
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 3296 = √ 2•2•2•2•2•103 =2•2•√ 206 =
± 4 • √ 206
√ 206 , rounded to 4 decimal digits, is 14.3527
So now we are looking at:
x = ( 44 ± 4 • 14.353 ) / -2
Two real solutions:
x =(44+√3296)/-2=22-2√ 206 = -50.705
or:
x =(44-√3296)/-2=22+2√ 206 = 6.705
Two solutions were found :
- x =(44-√3296)/-2=22+2√ 206 = 6.705
- x =(44+√3296)/-2=22-2√ 206 = -50.705
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