Solution - Adding, subtracting and finding the least common multiple

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "8.15" was replaced by "(815/100)". 4 more similar replacement(s)

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

      -(85/100)*t-(85/100)*t-(39/10)-(-(815/100))=0 

Step by step solution :

Step  1  :

            163
 Simplify   ———
            20 

Equation at the end of step  1  :

         85       85     39     163
  (((0-(———•t))-(———•t))-——)-(0-———)  = 0 
        100      100     10     20 

Step  2  :

            39
 Simplify   ——
            10

Equation at the end of step  2  :

         85       85     39  -163
  (((0-(———•t))-(———•t))-——)-————  = 0 
        100      100     10   20 

Step  3  :

            17
 Simplify   ——
            20

Equation at the end of step  3  :

         85      17     39  -163
  (((0-(———•t))-(——•t))-——)-————  = 0 
        100      20     10   20 

Step  4  :

            17
 Simplify   ——
            20

Equation at the end of step  4  :

           17          17t     39     -163
  (((0 -  (—— • t)) -  ———) -  ——) -  ————  = 0 
           20          20      10      20 

Step  5  :

Adding fractions which have a common denominator :

 5.1       Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 -17t - (17t)     -34t
 ————————————  =  ————
      20           20 

Equation at the end of step  5  :

   -34t    39     -163
  (———— -  ——) -  ————  = 0 
    20     10      20 

Step  6  :

Adding fractions which have a common denominator :

 6.1       Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 -17t - (39)     -17t - 39
 ———————————  =  —————————
     10             10    

Equation at the end of step  6  :

  (-17t - 39)    -163
  ——————————— -  ————  = 0 
      10          20 

Step  7  :

Step  8  :

Pulling out like terms :

 8.1     Pull out like factors :

   -17t - 39  =   -1 • (17t + 39) 

Calculating the Least Common Multiple :

 8.2    Find the Least Common Multiple

      The left denominator is :       10 

      The right denominator is :       20 

      Least Common Multiple:
      20 

Calculating Multipliers :

 8.3    Calculate multipliers for the two fractions


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = 2

   Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

 8.4      Rewrite the two fractions into equivalent fractions

   L. Mult. • L. Num.      (-17t-39) • 2
   ——————————————————  =   —————————————
         L.C.M                  20      

   R. Mult. • R. Num.      -163
   ——————————————————  =   ————
         L.C.M              20 

Adding fractions that have a common denominator :

 8.5       Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 (-17t-39) • 2 - (-163)     85 - 34t
 ——————————————————————  =  ————————
           20                  20   

Step  9  :

Pulling out like terms :

 9.1     Pull out like factors :

   85 - 34t  =   -17 • (2t - 5) 

Equation at the end of step  9  :

  -17 • (2t - 5)
  ——————————————  = 0 
        20      

Step  10  :

When a fraction equals zero :

 10.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

  -17•(2t-5)
  —————————— • 20 = 0 • 20
      20    

Now, on the left hand side, the  20  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   -17  •  (2t-5)  = 0

Equations which are never true :

 10.2      Solve :    -17   =  0

This equation has no solution.
A a non-zero constant never equals zero.

Solving a Single Variable Equation :

 10.3      Solve  :    2t-5 = 0 

 Add  5  to both sides of the equation : 
                      2t = 5
Divide both sides of the equation by 2:
                     t = 5/2 = 2.500

One solution was found :