Solution - Adding, subtracting and finding the least common multiple
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): ".0546" was replaced by "(0546/10000)". 3 more similar replacement(s)
Step by step solution :
Step 1 :
273
Simplify ————
5000
Equation at the end of step 1 :
475 339 273
((0-(————•(x2)))+(————•x))+———— = 0
1000 1000 5000
Step 2 :
339
Simplify ————
1000
Equation at the end of step 2 :
475 339 273 ((0-(————•(x2)))+(————•x))+———— = 0 1000 1000 5000Step 3 :
19 Simplify —— 40
Equation at the end of step 3 :
19 339x 273
((0 - (—— • x2)) + ————) + ———— = 0
40 1000 5000
Step 4 :
Equation at the end of step 4 :
19x2 339x 273
((0 - ————) + ————) + ———— = 0
40 1000 5000
Step 5 :
Calculating the Least Common Multiple :
5.1 Find the Least Common Multiple
The left denominator is : 40
The right denominator is : 1000
Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
2 | 3 | 3 | 3 |
5 | 1 | 3 | 3 |
Product of all Prime Factors | 40 | 1000 | 1000 |
Least Common Multiple:
1000
Calculating Multipliers :
5.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 25
Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
5.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. -19x2 • 25 —————————————————— = —————————— L.C.M 1000 R. Mult. • R. Num. 339x —————————————————— = ———— L.C.M 1000
Adding fractions that have a common denominator :
5.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
-19x2 • 25 + 339x 339x - 475x2
————————————————— = ————————————
1000 1000
Equation at the end of step 5 :
(339x - 475x2) 273
—————————————— + ———— = 0
1000 5000
Step 6 :
Step 7 :
Pulling out like terms :
7.1 Pull out like factors :
339x - 475x2 = -x • (475x - 339)
Calculating the Least Common Multiple :
7.2 Find the Least Common Multiple
The left denominator is : 1000
The right denominator is : 5000
Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
2 | 3 | 3 | 3 |
5 | 3 | 4 | 4 |
Product of all Prime Factors | 1000 | 5000 | 5000 |
Least Common Multiple:
5000
Calculating Multipliers :
7.3 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 5
Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
7.4 Rewrite the two fractions into equivalent fractions
L. Mult. • L. Num. -x • (475x-339) • 5 —————————————————— = ——————————————————— L.C.M 5000 R. Mult. • R. Num. 273 —————————————————— = ———— L.C.M 5000
Adding fractions that have a common denominator :
7.5 Adding up the two equivalent fractions
-x • (475x-339) • 5 + 273 -2375x2 + 1695x + 273
————————————————————————— = —————————————————————
5000 5000
Trying to factor by splitting the middle term
7.6 Factoring -2375x2 + 1695x + 273
The first term is, -2375x2 its coefficient is -2375 .
The middle term is, +1695x its coefficient is 1695 .
The last term, "the constant", is +273
Step-1 : Multiply the coefficient of the first term by the constant -2375 • 273 = -648375
Step-2 : Find two factors of -648375 whose sum equals the coefficient of the middle term, which is 1695 .
-648375 | + | 1 | = | -648374 | ||
-216125 | + | 3 | = | -216122 | ||
-129675 | + | 5 | = | -129670 | ||
-92625 | + | 7 | = | -92618 | ||
-49875 | + | 13 | = | -49862 | ||
-43225 | + | 15 | = | -43210 |
For tidiness, printing of 58 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 7 :
-2375x2 + 1695x + 273
————————————————————— = 0
5000
Step 8 :
When a fraction equals zero :
8.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
-2375x2+1695x+273
————————————————— • 5000 = 0 • 5000
5000
Now, on the left hand side, the 5000 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
-2375x2+1695x+273 = 0
Parabola, Finding the Vertex :
8.2 Find the Vertex of y = -2375x2+1695x+273
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens down and accordingly has a highest point (AKA absolute maximum) . We know this even before plotting "y" because the coefficient of the first term, -2375 , is negative (smaller than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 0.3568
Plugging into the parabola formula 0.3568 for x we can calculate the y -coordinate :
y = -2375.0 * 0.36 * 0.36 + 1695.0 * 0.36 + 273.0
or y = 575.424
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = -2375x2+1695x+273
Axis of Symmetry (dashed) {x}={ 0.36}
Vertex at {x,y} = { 0.36,575.42}
x -Intercepts (Roots) :
Root 1 at {x,y} = { 0.85, 0.00}
Root 2 at {x,y} = {-0.14, 0.00}
Solve Quadratic Equation by Completing The Square
8.3 Solving -2375x2+1695x+273 = 0 by Completing The Square .
Multiply both sides of the equation by (-1) to obtain positive coefficient for the first term:
2375x2-1695x-273 = 0 Divide both sides of the equation by 2375 to have 1 as the coefficient of the first term :
x2-(339/475)x-(273/2375) = 0
Add 273/2375 to both side of the equation :
x2-(339/475)x = 273/2375
Now the clever bit: Take the coefficient of x , which is 339/475 , divide by two, giving 339/950 , and finally square it giving 339/950
Add 339/950 to both sides of the equation :
On the right hand side we have :
273/2375 + 339/950 The common denominator of the two fractions is 4750 Adding (546/4750)+(1695/4750) gives 2241/4750
So adding to both sides we finally get :
x2-(339/475)x+(339/950) = 2241/4750
Adding 339/950 has completed the left hand side into a perfect square :
x2-(339/475)x+(339/950) =
(x-(339/950)) • (x-(339/950)) =
(x-(339/950))2
Things which are equal to the same thing are also equal to one another. Since
x2-(339/475)x+(339/950) = 2241/4750 and
x2-(339/475)x+(339/950) = (x-(339/950))2
then, according to the law of transitivity,
(x-(339/950))2 = 2241/4750
We'll refer to this Equation as Eq. #8.3.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x-(339/950))2 is
(x-(339/950))2/2 =
(x-(339/950))1 =
x-(339/950)
Now, applying the Square Root Principle to Eq. #8.3.1 we get:
x-(339/950) = √ 2241/4750
Add 339/950 to both sides to obtain:
x = 339/950 + √ 2241/4750
Since a square root has two values, one positive and the other negative
x2 - (339/475)x - (273/2375) = 0
has two solutions:
x = 339/950 + √ 2241/4750
or
x = 339/950 - √ 2241/4750
Note that √ 2241/4750 can be written as
√ 2241 / √ 4750
Solve Quadratic Equation using the Quadratic Formula
8.4 Solving -2375x2+1695x+273 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = -2375
B = 1695
C = 273
Accordingly, B2 - 4AC =
2873025 - (-2593500) =
5466525
Applying the quadratic formula :
-1695 ± √ 5466525
x = ——————————
-4750
Can √ 5466525 be simplified ?
Yes! The prime factorization of 5466525 is
3•5•5•23•3169
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 5466525 = √ 3•5•5•23•3169 =
± 5 • √ 218661
√ 218661 , rounded to 4 decimal digits, is 467.6120
So now we are looking at:
x = ( -1695 ± 5 • 467.612 ) / -4750
Two real solutions:
x =(-1695+√5466525)/-4750=(339-√ 218661 )/950= -0.135
or:
x =(-1695-√5466525)/-4750=(339+√ 218661 )/950= 0.849
Two solutions were found :
- x =(-1695-√5466525)/-4750=(339+√ 218661 )/950= 0.849
- x =(-1695+√5466525)/-4750=(339-√ 218661 )/950= -0.135
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