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Solution - Power equations

(-x3*(x2-y)2)/(7z2y3)
(-x^3*(x^2-y)^2)/(7z^2y^3)

Other Ways to Solve

Power equations

Step by Step Solution

Step  1  :

Equation at the end of step  1  :

                 ((x2)-y)
  (((49•(x3))•z)•————————)•(y-x2)
                  73z3y3 

Step  2  :

            x2 - y
 Simplify   ——————
            73z3y3

Trying to factor as a Difference of Squares :

 2.1      Factoring:  x2 - y 

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 - AB + AB - B2 =
         A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  x2  is the square of  x1 

Check :  y1   is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares

Equation at the end of step  2  :

                 (x2-y)
  (((49•(x3))•z)•——————)•(y-x2)
                 73z3y3

Step  3  :

Equation at the end of step  3  :

                (x2 - y)
  ((72x3 • z) • ————————) • (y - x2)
                 73z3y3 

Step  4  :

Dividing exponential expressions :

 4.1    z1 divided by z3 = z(1 - 3) = z(-2) = 1/z2

Dividing exponents :

 4.2    72   divided by   73   = 7(2 - 3) = 7(-1) = 1/71 = 1/7

Equation at the end of step  4  :

  x3 • (x2 - y)
  ————————————— • (y - x2)
      7z2y3    

Step  5  :

Trying to factor as a Difference of Squares :

 5.1      Factoring:  y-x2 

Check :  y1   is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares

 5.2    Rewrite   (y-x2)    as  (-1) •  (x2-y) 

Multiplying Exponential Expressions :

 5.3    Multiply  (x2-y)  by  (x2-y) 

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x2-y)  and the exponents are :
          1 , as  (x2-y)  is the same number as  (x2-y)1 
 and   1 , as  (x2-y)  is the same number as  (x2-y)1 
The product is therefore,  (x2-y)(1+1) = (x2-y)2 

Final result :

  -x3 • (x2 - y)2
  ———————————————
       7z2y3     

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