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Řešení - Trigonometry

- \frac{\sqrt{3}}{2}

-\frac{\sqrt{3}}{2}

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The period of trigonometric functions is 360 degrees.

$\sin (1320 °) = \sin (1320 - 360 °)$

Subtracting one integer from another.

$\sin (1320 - 360 °) = \sin (960 °)$

The period of trigonometric functions is 360 degrees.

$\sin (960 °) = \sin (960 - 360 °)$

Subtracting one integer from another.

$\sin (960 - 360 °) = \sin (600 °)$

The period of trigonometric functions is 360 degrees.

$\sin (600 °) = \sin (600 - 360 °)$

Subtracting one integer from another.

$\sin (600 - 360 °) = \sin (240 °)$

Reflecting the number with respect to 360 degrees.

$\sin (240 °) = \sin (360 - 120 °)$

The period of trigonometric functions is 360 degrees.

$\sin (360 - 120 °) = \sin (360 - 120 - 360 °)$

Removing or simplifying the same numbers on the top and bottom of a fraction.

$\sin (360 - 120 - 360 °) = \sin (- 120 °)$

Computing the sine of a negative angle.

$\sin (- 120 °) = - \sin (120 °)$

Reflecting the number with respect to 360 degrees.

$- \sin (120 °) = - \sin (180 - 60 °)$

Reflecting the sine function with respect to 180 degrees.

$- \sin (180 - 60 °) = - \sin (60 °)$

Computing the sine of 60 degrees.

$- \sin (60 °) = - \frac{\sqrt{3}}{2}$

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Goniometrie propojuje úhly, délky a periodické děje v matematice i fyzice.