Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}5& 4\\ -4& 2\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}5& 4\\ -4& 2\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}5& 4\\ -4& 2\end{array}\right]\right)$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& 0.8& 0.2& 0\\ -4& 2& 0& 1\end{array}\right]$$

R2 <- R2 + 4R1

$$\left[\begin{array}{cccccc}1& 0& 8& 0& 2& 0\\ 0& 5& 2& 0& 8& 1\end{array}\right]$$

R2 <- 5/26R2

$$\left[\begin{array}{cccc}1& 0.8& 0.2& 0\\ 0& 1& 0.153846& 0.192308\end{array}\right]$$

R1 <- R1 - 4/5R2

$$\left[\begin{array}{cccc}1& 0& 0.076923& -0.153846\\ 0& 1& 0.153846& 0.192308\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 076923& -0& 153846\\ 0& 153846& 0& 192308\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 076923& -0& 153846\\ 0& 153846& 0& 192308\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 076923& -0& 153846\\ 0& 153846& 0& 192308\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.