Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}4& 5\\ 3& -4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}4& 5\\ 3& -4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}4& 5\\ 3& -4\end{array}\right]\right)$$

R1 <- 1/4R1

$$\left[\begin{array}{cccc}1& 1.25& 0.25& 0\\ 3& -4& 0& 1\end{array}\right]$$

R2 <- R2 - 3R1

$$\left[\begin{array}{cccccc}1& 1& 25& 0& 25& 0\\ 0& -7& 75& -0& 75& 1\end{array}\right]$$

R2 <- -4/31R2

$$\left[\begin{array}{cccc}1& 1.25& 0.25& 0\\ 0& 1& 0.096774& -0.129032\end{array}\right]$$

R1 <- R1 - 5/4R2

$$\left[\begin{array}{cccc}1& 0& 0.129032& 0.16129\\ 0& 1& 0.096774& -0.129032\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 129032& 0& 16129\\ 0& 096774& -0& 129032\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 129032& 0& 16129\\ 0& 096774& -0& 129032\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 129032& 0& 16129\\ 0& 096774& -0& 129032\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.