Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}4& -3\\ -2& -4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}4& -3\\ -2& -4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}4& -3\\ -2& -4\end{array}\right]\right)$$

R1 <- 1/4R1

$$\left[\begin{array}{cccc}1& -0.75& 0.25& 0\\ -2& -4& 0& 1\end{array}\right]$$

R2 <- R2 + 2R1

$$\left[\begin{array}{cccccc}1& -0& 75& 0& 25& 0\\ 0& -5& 5& 0& 5& 1\end{array}\right]$$

R2 <- -2/11R2

$$\left[\begin{array}{cccc}1& -0.75& 0.25& 0\\ 0& 1& -0.090909& -0.181818\end{array}\right]$$

R1 <- R1 + 3/4R2

$$\left[\begin{array}{cccc}1& 0& 0.181818& -0.136364\\ 0& 1& -0.090909& -0.181818\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 181818& -0& 136364\\ -0& 090909& -0& 181818\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 181818& -0& 136364\\ -0& 090909& -0& 181818\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 181818& -0& 136364\\ -0& 090909& -0& 181818\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.