Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}3& 4\\ 5& -3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}3& 4\\ 5& -3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}3& 4\\ 5& -3\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& -3& 0& 1\\ 3& 4& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ 3& 4& 1& 0\end{array}\right]$$

R2 <- R2 - 3R1

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ 0& 5.8& 1& -0.6\end{array}\right]$$

R2 <- 5/29R2

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ 0& 1& 0.172414& -0.103448\end{array}\right]$$

R1 <- R1 + 3/5R2

$$\left[\begin{array}{cccc}1& 0& 0.103448& 0.137931\\ 0& 1& 0.172414& -0.103448\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 103448& 0& 137931\\ 0& 172414& -0& 103448\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 103448& 0& 137931\\ 0& 172414& -0& 103448\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 103448& 0& 137931\\ 0& 172414& -0& 103448\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.