Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}3& 3\\ 5& -4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}3& 3\\ 5& -4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}3& 3\\ 5& -4\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& -4& 0& 1\\ 3& 3& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& -0.8& 0& 0.2\\ 3& 3& 1& 0\end{array}\right]$$

R2 <- R2 - 3R1

$$\left[\begin{array}{cccc}1& -0.8& 0& 0.2\\ 0& 5.4& 1& -0.6\end{array}\right]$$

R2 <- 5/27R2

$$\left[\begin{array}{cccc}1& -0.8& 0& 0.2\\ 0& 1& 0.185185& -0.111111\end{array}\right]$$

R1 <- R1 + 4/5R2

$$\left[\begin{array}{cccc}1& 0& 0.148148& 0.111111\\ 0& 1& 0.185185& -0.111111\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 148148& 0& 111111\\ 0& 185185& -0& 111111\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 148148& 0& 111111\\ 0& 185185& -0& 111111\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 148148& 0& 111111\\ 0& 185185& -0& 111111\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.