Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}3& -2\\ 4& 5\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}3& -2\\ 4& 5\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}3& -2\\ 4& 5\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}4& 5& 0& 1\\ 3& -2& 1& 0\end{array}\right]$$

R1 <- 1/4R1

$$\left[\begin{array}{cccc}1& 1.25& 0& 0.25\\ 3& -2& 1& 0\end{array}\right]$$

R2 <- R2 - 3R1

$$\left[\begin{array}{cccc}1& 1.25& 0& 0.25\\ 0& -5.75& 1& -0.75\end{array}\right]$$

R2 <- -4/23R2

$$\left[\begin{array}{cccc}1& 1.25& 0& 0.25\\ 0& 1& -0.173913& 0.130435\end{array}\right]$$

R1 <- R1 - 5/4R2

$$\left[\begin{array}{cccc}1& 0& 0.217391& 0.086957\\ 0& 1& -0.173913& 0.130435\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 217391& 0& 086957\\ -0& 173913& 0& 130435\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 217391& 0& 086957\\ -0& 173913& 0& 130435\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 217391& 0& 086957\\ -0& 173913& 0& 130435\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.