Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}3& -1\\ 5& 2\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}3& -1\\ 5& 2\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}3& -1\\ 5& 2\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& 2& 0& 1\\ 3& -1& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& 0.4& 0& 0.2\\ 3& -1& 1& 0\end{array}\right]$$

R2 <- R2 - 3R1

$$\left[\begin{array}{cccc}1& 0.4& 0& 0.2\\ 0& -2.2& 1& -0.6\end{array}\right]$$

R2 <- -5/11R2

$$\left[\begin{array}{cccc}1& 0.4& 0& 0.2\\ 0& 1& -0.454545& 0.272727\end{array}\right]$$

R1 <- R1 - 2/5R2

$$\left[\begin{array}{cccc}1& 0& 0.181818& 0.090909\\ 0& 1& -0.454545& 0.272727\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 181818& 0& 090909\\ -0& 454545& 0& 272727\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 181818& 0& 090909\\ -0& 454545& 0& 272727\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 181818& 0& 090909\\ -0& 454545& 0& 272727\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.