Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}2& -4\\ 5& 1\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}2& -4\\ 5& 1\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}2& -4\\ 5& 1\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& 1& 0& 1\\ 2& -4& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& 0.2& 0& 0.2\\ 2& -4& 1& 0\end{array}\right]$$

R2 <- R2 - 2R1

$$\left[\begin{array}{cccc}1& 0.2& 0& 0.2\\ 0& -4.4& 1& -0.4\end{array}\right]$$

R2 <- -5/22R2

$$\left[\begin{array}{cccc}1& 0.2& 0& 0.2\\ 0& 1& -0.227273& 0.090909\end{array}\right]$$

R1 <- R1 - 1/5R2

$$\left[\begin{array}{cccc}1& 0& 0.045455& 0.181818\\ 0& 1& -0.227273& 0.090909\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 045455& 0& 181818\\ -0& 227273& 0& 090909\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 045455& 0& 181818\\ -0& 227273& 0& 090909\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 045455& 0& 181818\\ -0& 227273& 0& 090909\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.