Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}2& -4\\ 5& -3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}2& -4\\ 5& -3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}2& -4\\ 5& -3\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& -3& 0& 1\\ 2& -4& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ 2& -4& 1& 0\end{array}\right]$$

R2 <- R2 - 2R1

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ 0& -2.8& 1& -0.4\end{array}\right]$$

R2 <- -5/14R2

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ 0& 1& -0.357143& 0.142857\end{array}\right]$$

R1 <- R1 + 3/5R2

$$\left[\begin{array}{cccc}1& 0& -0.214286& 0.285714\\ 0& 1& -0.357143& 0.142857\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}-0& 214286& 0& 285714\\ -0& 357143& 0& 142857\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}-0& 214286& 0& 285714\\ -0& 357143& 0& 142857\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}-0& 214286& 0& 285714\\ -0& 357143& 0& 142857\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.