Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}2& -1\\ 5& 4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}2& -1\\ 5& 4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}2& -1\\ 5& 4\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& 4& 0& 1\\ 2& -1& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& 0.8& 0& 0.2\\ 2& -1& 1& 0\end{array}\right]$$

R2 <- R2 - 2R1

$$\left[\begin{array}{cccc}1& 0.8& 0& 0.2\\ 0& -2.6& 1& -0.4\end{array}\right]$$

R2 <- -5/13R2

$$\left[\begin{array}{cccc}1& 0.8& 0& 0.2\\ 0& 1& -0.384615& 0.153846\end{array}\right]$$

R1 <- R1 - 4/5R2

$$\left[\begin{array}{cccc}1& 0& 0.307692& 0.076923\\ 0& 1& -0.384615& 0.153846\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 307692& 0& 076923\\ -0& 384615& 0& 153846\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 307692& 0& 076923\\ -0& 384615& 0& 153846\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 307692& 0& 076923\\ -0& 384615& 0& 153846\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.