Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}1& 3\\ -4& 5\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}1& 3\\ -4& 5\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}1& 3\\ -4& 5\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}-4& 5& 0& 1\\ 1& 3& 1& 0\end{array}\right]$$

R1 <- -1/4R1

$$\left[\begin{array}{cccc}1& -1.25& 0& -0.25\\ 1& 3& 1& 0\end{array}\right]$$

R2 <- R2 - R1

$$\left[\begin{array}{cccc}1& -1.25& 0& -0.25\\ 0& 4.25& 1& 0.25\end{array}\right]$$

R2 <- 4/17R2

$$\left[\begin{array}{cccc}1& -1.25& 0& -0.25\\ 0& 1& 0.235294& 0.058824\end{array}\right]$$

R1 <- R1 + 5/4R2

$$\left[\begin{array}{cccc}1& 0& 0.294118& -0.176471\\ 0& 1& 0.235294& 0.058824\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}0& 294118& -0& 176471\\ 0& 235294& 0& 058824\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}0& 294118& -0& 176471\\ 0& 235294& 0& 058824\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}0& 294118& -0& 176471\\ 0& 235294& 0& 058824\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.