Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}-4& 5\\ 5& 3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}-4& 5\\ 5& 3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}-4& 5\\ 5& 3\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& 3& 0& 1\\ -4& 5& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& 0.6& 0& 0.2\\ -4& 5& 1& 0\end{array}\right]$$

R2 <- R2 + 4R1

$$\left[\begin{array}{cccc}1& 0.6& 0& 0.2\\ 0& 7.4& 1& 0.8\end{array}\right]$$

R2 <- 5/37R2

$$\left[\begin{array}{cccc}1& 0.6& 0& 0.2\\ 0& 1& 0.135135& 0.108108\end{array}\right]$$

R1 <- R1 - 3/5R2

$$\left[\begin{array}{cccc}1& 0& -0.081081& 0.135135\\ 0& 1& 0.135135& 0.108108\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}-0& 081081& 0& 135135\\ 0& 135135& 0& 108108\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}-0& 081081& 0& 135135\\ 0& 135135& 0& 108108\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}-0& 081081& 0& 135135\\ 0& 135135& 0& 108108\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.