Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}-4& 3\\ 5& 4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}-4& 3\\ 5& 4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}-4& 3\\ 5& 4\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& 4& 0& 1\\ -4& 3& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& 0.8& 0& 0.2\\ -4& 3& 1& 0\end{array}\right]$$

R2 <- R2 + 4R1

$$\left[\begin{array}{cccc}1& 0.8& 0& 0.2\\ 0& 6.2& 1& 0.8\end{array}\right]$$

R2 <- 5/31R2

$$\left[\begin{array}{cccc}1& 0.8& 0& 0.2\\ 0& 1& 0.16129& 0.129032\end{array}\right]$$

R1 <- R1 - 4/5R2

$$\left[\begin{array}{cccc}1& 0& -0.129032& 0.096774\\ 0& 1& 0.16129& 0.129032\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}-0& 129032& 0& 096774\\ 0& 16129& 0& 129032\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}-0& 129032& 0& 096774\\ 0& 16129& 0& 129032\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}-0& 129032& 0& 096774\\ 0& 16129& 0& 129032\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.