Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}-4& -3\\ 5& -2\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}-4& -3\\ 5& -2\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}-4& -3\\ 5& -2\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& -2& 0& 1\\ -4& -3& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& -0.4& 0& 0.2\\ -4& -3& 1& 0\end{array}\right]$$

R2 <- R2 + 4R1

$$\left[\begin{array}{cccc}1& -0.4& 0& 0.2\\ 0& -4.6& 1& 0.8\end{array}\right]$$

R2 <- -5/23R2

$$\left[\begin{array}{cccc}1& -0.4& 0& 0.2\\ 0& 1& -0.217391& -0.173913\end{array}\right]$$

R1 <- R1 + 2/5R2

$$\left[\begin{array}{cccc}1& 0& -0.086957& 0.130435\\ 0& 1& -0.217391& -0.173913\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}-0& 086957& 0& 130435\\ -0& 217391& -0& 173913\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}-0& 086957& 0& 130435\\ -0& 217391& -0& 173913\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}-0& 086957& 0& 130435\\ -0& 217391& -0& 173913\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.