Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}-4& -2\\ 5& -3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}-4& -2\\ 5& -3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}-4& -2\\ 5& -3\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& -3& 0& 1\\ -4& -2& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ -4& -2& 1& 0\end{array}\right]$$

R2 <- R2 + 4R1

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ 0& -4.4& 1& 0.8\end{array}\right]$$

R2 <- -5/22R2

$$\left[\begin{array}{cccc}1& -0.6& 0& 0.2\\ 0& 1& -0.227273& -0.181818\end{array}\right]$$

R1 <- R1 + 3/5R2

$$\left[\begin{array}{cccc}1& 0& -0.136364& 0.090909\\ 0& 1& -0.227273& -0.181818\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}-0& 136364& 0& 090909\\ -0& 227273& -0& 181818\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}-0& 136364& 0& 090909\\ -0& 227273& -0& 181818\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}-0& 136364& 0& 090909\\ -0& 227273& -0& 181818\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.