Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}-4& -2\\ -3& 4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}-4& -2\\ -3& 4\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}-4& -2\\ -3& 4\end{array}\right]\right)$$

R1 <- -1/4R1

$$\left[\begin{array}{cccc}1& 0.5& -0.25& 0\\ -3& 4& 0& 1\end{array}\right]$$

R2 <- R2 + 3R1

$$\left[\begin{array}{cccccc}1& 0& 5& -0& 25& 0\\ 0& 5& 5& -0& 75& 1\end{array}\right]$$

R2 <- 2/11R2

$$\left[\begin{array}{cccc}1& 0.5& -0.25& 0\\ 0& 1& -0.136364& 0.181818\end{array}\right]$$

R1 <- R1 - 1/2R2

$$\left[\begin{array}{cccc}1& 0& -0.181818& -0.090909\\ 0& 1& -0.136364& 0.181818\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}-0& 181818& -0& 090909\\ -0& 136364& 0& 181818\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}-0& 181818& -0& 090909\\ -0& 136364& 0& 181818\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}-0& 181818& -0& 090909\\ -0& 136364& 0& 181818\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.