Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}-2& 2\\ 5& 2\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}-2& 2\\ 5& 2\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}-2& 2\\ 5& 2\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}5& 2& 0& 1\\ -2& 2& 1& 0\end{array}\right]$$

R1 <- 1/5R1

$$\left[\begin{array}{cccc}1& 0.4& 0& 0.2\\ -2& 2& 1& 0\end{array}\right]$$

R2 <- R2 + 2R1

$$\left[\begin{array}{cccc}1& 0.4& 0& 0.2\\ 0& 2.8& 1& 0.4\end{array}\right]$$

R2 <- 5/14R2

$$\left[\begin{array}{cccc}1& 0.4& 0& 0.2\\ 0& 1& 0.357143& 0.142857\end{array}\right]$$

R1 <- R1 - 2/5R2

$$\left[\begin{array}{cccc}1& 0& -0.142857& 0.142857\\ 0& 1& 0.357143& 0.142857\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}-0& 142857& 0& 142857\\ 0& 357143& 0& 142857\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}-0& 142857& 0& 142857\\ 0& 357143& 0& 142857\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}-0& 142857& 0& 142857\\ 0& 357143& 0& 142857\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.