Řešení - Základní operace s maticemi

$$\in v\left(\left[\begin{array}{cc}-1& -2\\ -4& 3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvPlan

$$\in v\left(\left[\begin{array}{cc}-1& -2\\ -4& 3\end{array}\right]\right)$$

MatrixCoreOperationsStep2TransitionInvCheck

$$\in v\left(\left[\begin{array}{cc}-1& -2\\ -4& 3\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}-4& 3& 0& 1\\ -1& -2& 1& 0\end{array}\right]$$

R1 <- -1/4R1

$$\left[\begin{array}{cccc}1& -0.75& 0& -0.25\\ -1& -2& 1& 0\end{array}\right]$$

R2 <- R2 + R1

$$\left[\begin{array}{cccc}1& -0.75& 0& -0.25\\ 0& -2.75& 1& -0.25\end{array}\right]$$

R2 <- -4/11R2

$$\left[\begin{array}{cccc}1& -0.75& 0& -0.25\\ 0& 1& -0.363636& 0.090909\end{array}\right]$$

R1 <- R1 + 3/4R2

$$\left[\begin{array}{cccc}1& 0& -0.272727& -0.181818\\ 0& 1& -0.363636& 0.090909\end{array}\right]$$

MatrixCoreOperationsStep2TextUnitInv

$$\left[\begin{array}{cccc}-0& 272727& -0& 181818\\ -0& 363636& 0& 090909\end{array}\right]$$

MatrixCoreOperationsStep3TransitionConclusionInv

$$\left[\begin{array}{cccc}-0& 272727& -0& 181818\\ -0& 363636& 0& 090909\end{array}\right]$$

MatrixCoreOperationsStep3TransitionStudyTipInv

$$\left[\begin{array}{cccc}-0& 272727& -0& 181818\\ -0& 363636& 0& 090909\end{array}\right]$$

Zobrazte konečný maticový nebo skalární výsledek v kanonickém tvaru pro stabilní směrování a kontrolu.