সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=760$$ এবং সাধারণ অনুপাত: $$r=0.002631578947368421$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=760$$

$$a_2=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{2-1}=760\cdot {0.002631578947368421}^1=760\cdot 0.002631578947368421=2$$

$$a_3=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{3-1}=760\cdot {0.002631578947368421}^2=760\cdot 6.925207756232687E-06=0.005263157894736842$$

$$a_4=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{4-1}=760\cdot {0.002631578947368421}^3=760\cdot 1.8224230937454438E-08=1.3850415512465373E-05$$

$$a_5=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{5-1}=760\cdot {0.002631578947368421}^4=760\cdot 4.795850246698536E-11=3.6448461874908876E-08$$

$$a_6=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{6-1}=760\cdot {0.002631578947368421}^5=760\cdot 1.2620658543943516E-13=9.591700493397072E-11$$

$$a_7=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{7-1}=760\cdot {0.002631578947368421}^6=760\cdot 3.3212259326167147E-16=2.524131708788703E-13$$

$$a_8=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{8-1}=760\cdot {0.002631578947368421}^7=760\cdot 8.740068243728196E-19=6.642451865233428E-16$$

$$a_9=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{9-1}=760\cdot {0.002631578947368421}^8=760\cdot 2.3000179588758412E-21=1.748013648745639E-18$$

$$a_{10}=a_1·r^{n-1}=760\cdot {0.002631578947368421}^{10-1}=760\cdot {0.002631578947368421}^9=760\cdot 6.05267883914695E-24=4.600035917751682E-21$$