সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=72$$ এবং সাধারণ অনুপাত: $$r=0.013888888888888888$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=72$$

$$a_2=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{2-1}=72\cdot {0.013888888888888888}^1=72\cdot 0.013888888888888888=1$$

$$a_3=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{3-1}=72\cdot {0.013888888888888888}^2=72\cdot 0.00019290123456790122=0.013888888888888888$$

$$a_4=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{4-1}=72\cdot {0.013888888888888888}^3=72\cdot 2.679183813443072E-06=0.0001929012345679012$$

$$a_5=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{5-1}=72\cdot {0.013888888888888888}^4=72\cdot 3.721088629782045E-08=2.679183813443072E-06$$

$$a_6=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{6-1}=72\cdot {0.013888888888888888}^5=72\cdot 5.168178652475062E-10=3.721088629782044E-08$$

$$a_7=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{7-1}=72\cdot {0.013888888888888888}^6=72\cdot 7.178025906215363E-12=5.168178652475062E-10$$

$$a_8=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{8-1}=72\cdot {0.013888888888888888}^7=72\cdot 9.969480425299115E-14=7.178025906215362E-12$$

$$a_9=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{9-1}=72\cdot {0.013888888888888888}^8=72\cdot 1.3846500590693213E-15=9.969480425299113E-14$$

$$a_{10}=a_1·r^{n-1}=72\cdot {0.013888888888888888}^{10-1}=72\cdot {0.013888888888888888}^9=72\cdot 1.923125082040724E-17=1.3846500590693213E-15$$