সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=65$$ এবং সাধারণ অনুপাত: $$r=2.2$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=65$$

$$a_2=a_1·r^{n-1}=65\cdot {2.2}^{2-1}=65\cdot {2.2}^1=65\cdot 2.2=143$$

$$a_3=a_1·r^{n-1}=65\cdot {2.2}^{3-1}=65\cdot {2.2}^2=65\cdot 4.840000000000001=314.6$$

$$a_4=a_1·r^{n-1}=65\cdot {2.2}^{4-1}=65\cdot {2.2}^3=65\cdot 10.648000000000003=692.1200000000002$$

$$a_5=a_1·r^{n-1}=65\cdot {2.2}^{5-1}=65\cdot {2.2}^4=65\cdot 23.425600000000006=1522.6640000000004$$

$$a_6=a_1·r^{n-1}=65\cdot {2.2}^{6-1}=65\cdot {2.2}^5=65\cdot 51.53632000000002=3349.8608000000013$$

$$a_7=a_1·r^{n-1}=65\cdot {2.2}^{7-1}=65\cdot {2.2}^6=65\cdot 113.37990400000005=7369.693760000004$$

$$a_8=a_1·r^{n-1}=65\cdot {2.2}^{8-1}=65\cdot {2.2}^7=65\cdot 249.43578880000015=16213.32627200001$$

$$a_9=a_1·r^{n-1}=65\cdot {2.2}^{9-1}=65\cdot {2.2}^8=65\cdot 548.7587353600004=35669.31779840003$$

$$a_{10}=a_1·r^{n-1}=65\cdot {2.2}^{10-1}=65\cdot {2.2}^9=65\cdot 1207.269217792001=78472.49915648006$$