সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=52$$ এবং সাধারণ অনুপাত: $$r=11.538461538461538$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=52$$

$$a_2=a_1·r^{n-1}=52\cdot {11.538461538461538}^{2-1}=52\cdot {11.538461538461538}^1=52\cdot 11.538461538461538=600$$

$$a_3=a_1·r^{n-1}=52\cdot {11.538461538461538}^{3-1}=52\cdot {11.538461538461538}^2=52\cdot 133.1360946745562=6923.076923076923$$

$$a_4=a_1·r^{n-1}=52\cdot {11.538461538461538}^{4-1}=52\cdot {11.538461538461538}^3=52\cdot 1536.1857077833408=79881.65680473372$$

$$a_5=a_1·r^{n-1}=52\cdot {11.538461538461538}^{5-1}=52\cdot {11.538461538461538}^4=52\cdot 17725.219705192394=921711.4246700045$$

$$a_6=a_1·r^{n-1}=52\cdot {11.538461538461538}^{6-1}=52\cdot {11.538461538461538}^5=52\cdot 204521.765829143=10635131.823115436$$

$$a_7=a_1·r^{n-1}=52\cdot {11.538461538461538}^{7-1}=52\cdot {11.538461538461538}^6=52\cdot 2359866.528797804=122713059.4974858$$

$$a_8=a_1·r^{n-1}=52\cdot {11.538461538461538}^{8-1}=52\cdot {11.538461538461538}^7=52\cdot 27229229.178436197=1415919917.2786822$$

$$a_9=a_1·r^{n-1}=52\cdot {11.538461538461538}^{9-1}=52\cdot {11.538461538461538}^8=52\cdot 314183413.59734076=16337537507.06172$$

$$a_{10}=a_1·r^{n-1}=52\cdot {11.538461538461538}^{10-1}=52\cdot {11.538461538461538}^9=52\cdot 3625193233.81547=188510048158.40445$$